An Electrical Engineer's response
[-e[SUP](iπ)[/SUP]][SUP]½[/SUP] 2[SUP]3[/SUP] Σ Ω[SUP]-1[/SUP] π
... and I might even go back for Ω[SUP]-1[/SUP], τ/π.
Bill, I'm impressed. How were you able to access an equations mode in this post. BTW, as electrical enginners, we should be using j instead of i for the unit imaginary.